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The function j(x)=39x represents the number of the jumping jacks j(x) you can do in x minutes how many jumping jacks can you do in 5 minutes

Respuesta :

CaptainBoom

Put x=5 in above function. J(x)= 39x. J(5) = 39x5 = 195.

calculista

Answer:

[tex]195\ jumping\ jacks[/tex]

Step-by-step explanation:

Let

x------> the time in minutes

j(x)----> the number of the jumping jacks

we have

[tex]j(x)=39x[/tex]

This is a linear direct variation

The slope is equal to [tex]m=39\frac{jumping\ jacks}{minute}[/tex]

To find how many jumping jacks can you do in [tex]5[/tex] minutes

Substitute the value of [tex]x=5\ min[/tex] in the function j(x)

so

[tex]j(5)=39(5)=195\ jumping\ jacks[/tex]

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