Respuesta :

Ckaranja
Line 1;
y=-10x+1
Gradient m= -10
Gradient of line 2= 1/10
[tex] \frac{y-5}{x-7} = \frac{1}{10} [/tex]
y-5=[tex] \frac{1}{10} {x-7}[/tex]
y-5=[tex] \frac{1}{10} x- \frac{7}{10} [/tex]
y=[tex] \frac{1}{10} x- \frac{43}{10} [/tex]

akposevictor

The equation of the perpendicular line is: y = 1/10x + 13/2.

How to Find the Equation of Perpendicular Lines?

Lines that are perpendicular to each other have the slope that are negative reciprocals. Therefore, since the slope of y = -10x + 1 is -10, the line perpendicular to it will have a slope (m) of: 1/10.

Plug in (x, y) = (5, 7) and m = 1/10 into y = mx + b to find b.

7 = 1/10(5) + b

7 = 1/2 + b

7 - 1/2 = b

13/2  = b

Substitute b = 13/2 and m = 1/10 into y = mx + b

y = 1/10x + 13/2

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