Respuesta :
Answer:
[tex]368 +100 +10 +10 +10 +1+1 = 500[/tex]
Step-by-step explanation:
We have to count from 368 to 500. Basically we have to reach from 368 to 500.
This could be similar to jumping on a number line from 368 to 500.
We could use ones, tens and hundreds to do so.
If we take a jump of 100 from 368, then,
[tex]368 + 100 = 468[/tex], we reach 468.
If we take a jump of three tens from 468, then,
[tex]468 + 10 = 478\\478 + 10 =488\\488 + 10 = 498[/tex], we reach 498.
If we take a jump of two ones, then,
[tex]498 + 1 = 499\\499 + 1 =500[/tex], hence, we reach 500.
Thus, we have to take 1 jump of 100, three jumps of ten and two jumps of one to reach 500 from 368.
The number of count by ones from 368 to 500 is [tex]\boxed{132{\text{ one's}}}.[/tex]
Further explanation:
Given:
The numbers are 500 and 368.
Explanation:
The place values are only natural numbers.
The base ten systems represent the position of a place value.
We have to find the number of count by ones from 368 to 500.
The difference between 368 and 500 can be calculated as follows,
[tex]\begin{aligned}{\text{Difference}}&= 500 - 368\\&= 132\\\end{aligned}[/tex]
The number 500 in base ten-system can also be represented as follows,
[tex]\boxed{500 = 500 + 0 + 0}[/tex]
The number 368 in base ten-system can also be represented as follows,
[tex]\boxed{368 = 300 + 60 + 8}[/tex]
The number 132 in base ten-system can also be represented as follows,
[tex]\boxed{132 = 100 + 30 + 2}[/tex]
The number of count by ones from 368 to 500 is [tex]\boxed{132{\text{ one's}}}.[/tex]
Learn more
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Answer details:
Grade: High school
Subject: Mathematics
Chapter: Number system
Keywords: factor, factorization, polynomial, quadratic, cubic, greatest common factor, groups, multiplication, product, identities, common factor, expression, terms, grouping.
