Respuesta :
Oxidation:
Li ----> Li+ + e- ...(1)
Reduction:
H2 + 2e- ------> 2H- ...(2)
Multiplying (1) by 2 and adding in (2) gives the required equation....
2Li + H2 ---------> 2LiH
Li ----> Li+ + e- ...(1)
Reduction:
H2 + 2e- ------> 2H- ...(2)
Multiplying (1) by 2 and adding in (2) gives the required equation....
2Li + H2 ---------> 2LiH
The half -reactions for the given redox reaction are:
[tex]\rm Li\;\rightarrow\;Li^+\;+\;e^-[/tex]
[tex]\rm H_2\;+\;2e^-\;\rightarrow\;2\;H^+[/tex]
In an electrolytic cell, under the influence of the electric current, the transfer of electrons takes place. The transfer of electrons has been mediated by the redox reaction.
The redox reaction has been the oxidation and reduction of the elements.
The half-reaction of the redox reaction has been the oxidation and the reduction reaction.
The oxidation of the reaction is the loss of electrons. The oxidation reaction will be:
[tex]\rm Li\;\rightarrow\;Li^+\;+\;e^-[/tex]
The reduction has been the gain of electrons. The reduction reaction can be written as:
[tex]\rm H_2\;+\;2e^-\;\rightarrow\;2\;H^+[/tex]
The addition of two half-reactions results in the final redox reaction.
[tex]\rm 2\;Li^+\;+\;H_2\;\rightarrow\;2\;LiH[/tex]
For more information about the redox reaction, refer to the link:
https://brainly.com/question/13978139
