Answer:
Graph is attached
6.5 feet
Step-by-step explanation:
The function is
[tex]h=-16t^2+25t+5[/tex]
We need to find the height of the ball when the ball has been in the air for 1.5 seconds.
So, [tex]t=1.5[/tex]
[tex]h=-16\times 1.5^2+25\times 1.5+5\\\Rightarrow h=6.5\ \text{feet}[/tex]
The ball is [tex]6.5\ \text{feet}[/tex] from the ground when the ball has been in the air for 1.5 seconds.
The graph denotes the path of the ball.
