The electrostatic force between the moon and the planet can be neglected. Hence, option (A) is correct.
The given problem is based on the comparison between the gravitational force and electrostatic force. Consider the two bodies as moon and a planet such that the force exerted between the moon and the planet is given as,
[tex]F_{g}=\dfrac{G\times M \times m}{r^{2}}[/tex] ..................................................(1)
Here, G is the gravitational constant, M is the mass of moon, m is the mass of planet and r is the distance between the moon and the planet.
And the electrostatic force is the force between the two charged entities on moon and the planet. So, it is given as,
[tex]F_{e}=\dfrac{k \times Q \times q}{r^{2}}[/tex] ....................................................(2)
Here, k is the Coulomb's constant, Q is the charge entity at moon and q is the charged entity on planet.
The forces obtained in equation (1) and (2) depends on the masses and charges, which clearly signifies that the masses have more numerical value than charges, hence the electrostatic force will leave much lesser influence than gravitational force. So, it can be neglected.
Thus, we conclude that the electrostatic force between the moon and the planet can be neglected. Hence, option (A) is correct.
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