Theorem A line parallel to one side of a triangle divides the other two proportionately

In the below segment DE is parallel to segment BC and segment EF is parallel to AB

Theorem A line parallel to one side of a triangle divides the other two proportionately In the below segment DE is parallel to segment BC and segment EF is para class=

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The correct answer is C) Segment BD = 20.

Based on the triangle proportionality theorem, if DE is parallel to BC and EF to AB, the statement that proves the theorem true is: B. Segment BD = 15.

What is the Triangle Proportionality Theorem?

  • Triangle proportionality theorem states that when a line that is parallel to one side of a triangle intersects the other two lines, it divides the other two lines proportionately.
  • The theorem is what is given in this question, and it implies that: AD/BD = AE/CE

Given:

AD = 18

BD = ?

AE = 24

CE = 20

Thus:

18/BD = 24/20

  • Cross multiply

BD = (20 × 18)/24

BD = 15

Therefore, based on the triangle proportionality theorem, if DE is parallel to BC and EF to AB, the statement that proves the theorem true is: B. Segment BD = 15.

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