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Arrange the aqueous solutions from the most acidic to the most basic, at 25 C.
Acidic
[OH | = 1x 10^-7 M
[OHT|=1× 10^-9 M
[H"] = 1 x 10^-3 M
pH = 11

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Answer:

See explanation below

Explanation:

If [OH | = 1x 10^-7 M then [H^+] = 1 * 10^-14/1x 10^-7 = 1x 10^-7 M

pH = - log [H^+]  = -log [1x 10^-7]

pH = 7

If [OH | = 1x 10^-9 M then [H^+] = 1 * 10^-14/1x 10^-9 = 1x 10^-5 M

pH = - log [H^+]  = -log [1x 10^-5]

pH = 5

[H^+] = 1 x 10^-3 M

pH = - log [H^+]  = -log [1x 10^-3]

pH = 3

Hence the decreasing acidity;

pH 3 > pH 5 > pH 7 > pH 11

The most acidic is pH 3 while the most basic is pH 11

The given aqueous solutions begin from the most acidic to the most basic at a given temperature of 25°C would be:

pH 3 > pH 5 > pH 7 > pH 11

  • The pH scale is employed to denote the nature of a substance in the form of its acidic or basic properties.
  • A pH level below 7 denotes the substance to be acidic while 7 stands for neutral and more than that denotes basic.
  • In order to check the acidic or basic nature of given substances, they need to be converted into pH form through the formula:

[tex][OH | = 1[/tex]x [tex]10^-7 M[/tex]

so,

[tex][H^+] =[/tex] [tex]1[/tex] × [tex]10^-14/1[/tex]x [tex]10^-7[/tex]

[tex]= 1[/tex] x [tex]10^-7 M[/tex]

[tex]pH = - log [H^+][/tex]

[tex]= -log [1[/tex] x [tex]10^-7[/tex]}

∵ pH = 7

Similarly, the others we get as:

pH = 5

pH = 3

and pH = 11

As we know the lower the rank, the more acidic the solution is.

Thus, the correct arrangement from acidic to basic would be pH 3 > pH 5 > pH 7 > pH 11

Learn more about "Solution" here:

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