I need help! What is the solution to the equation?
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[tex]\displaystyle\tt\leadsto \sqrt[3]{x-1}=4[/tex]
[tex]\displaystyle\tt\leadsto x-1 = 4^3[/tex]
[tex]\displaystyle\tt\leadsto x = 4^3 + 1 [/tex]
[tex]\displaystyle\tt\leadsto x = 64 + 1 [/tex]
[tex]\displaystyle\leadsto \underline{\boxed{\textbf{\textsf{x = 65}}}}[/tex]