Answer:
t = 14 s
Explanation:
First, we need to find the acceleration of the meteor by using Newton's s Second Law, as follows:
[tex]F = ma[/tex]
where,
F = Unbalanced Force = 100000 N
m = mass of meteor = 70 kg
a = acceleration of meteor = ?
Therefore,
[tex]100000\ N = (70\ kg)(a)\\a = \frac{(100000\ N)}{70\ kg}\\\\a = 1428.57\ m/s^2[/tex]
a = -1428.57 m/s² (negative sign de to deceleration)
Now, we use general formula of acceleration to find time:
[tex]a = \frac{\Delta v}{t}\\\\t = \frac{\Delta v}{a}[/tex]
where,
t = time taken = ?
Δv = change in speed = 0m/s - 20000 m/s = - 20000 m/s
Therefore,
[tex]t = \frac{- 20000\ m/s}{-1428.57\ m/s^2}\\\\[/tex]
t = 14 s
