Answer:
a. A data set with 14, 68, and s41.
Step-by-step explanation:
For a normally distributed data set; Q₁ and Q₃ will be 0.6745 × 2 = 1.349 standard deviation.
The interquartile range IQR = Q₃ - Q₁ = 1.349 × [tex]{\sigma}[/tex]
Q₁ Q₃ [tex]{\sigma}[/tex] IQR = Q₃ - Q₁ 1.349 × [tex]{\sigma}[/tex]
a. 14 68 41 = 68 - 14 1.349 × 41
= 54 = 55.309
b. 1330 2940 2440 = 2940 - 1330 1.349 × 2440
= 1610 = 3291.56
c. 2.2 7.3 2.1 = 7.3 - 2.2 1.349 × 2.1
= 5.1 = 2.8329
d. 105 270 33 = 270 - 105 1.349 × 33
= 165 = 44.517
From the above calculation, we will see that option a have a data set that is approximately normal.
