Respuesta :

maacastrobr

Answer:

b. 7.5 x 10^-3

Explanation:

To solve this problem we need to keep in mind the definition of molarity:

  • Molarity = moles of solute / liters of solution

With the above information in mind it is possible to calculate the moles of solute, given the volume (10 mL) and concentration (0.75 M) of the solution:

  • First we convert 10 mL to L ⇒ 10 mL / 1000 = 0.01 L

Then we calculate the moles of AgNO₃:

  • moles of solute = Molarity * Liters of solution
  • 0.01 L * 0.75 M = 7.5x10⁻³ mol AgNO₃

One mole of AgNO₃ contains one mole of Ag⁺, thus the number of Ag⁺ moles is also 7.5x10⁻³.

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