Answer:
The mistake in Kevin's calculation is when calculating P(Red or Green).
Step-by-step explanation:
Given
[tex]Sections = 10[/tex]
[tex]Spins = 180[/tex]
[tex]Red, Blue, Green, Yellow, Purple = 2\ each[/tex]
Required
Spot the mistake in Kevin's calculation
From the question, we have that:
Kevin's calculation
[tex]P(Red\ or\ Green) = \frac{2}{10}[/tex]
Number of times;
[tex]Times = \frac{2}{10} *180 = 36[/tex]
The mistake in Kevin's calculation is when calculating P(Red or Green).
[tex]P(Red\ or\ Green) = \frac{Number\ of\ red\ or\ green}{Total}[/tex]
He considered only one section instead of both sections
The correction is:
Since, there are 2 green sections and 2 red sections.
The equation becomes
[tex]P(Red\ or\ Green) = \frac{2 + 2}{10}[/tex]
[tex]P(Red\ or\ Green) = \frac{4}{10}[/tex]
And the number of times is:
[tex]Times = \frac{4}{10} * 180[/tex]
[tex]Times = \frac{720}{10}[/tex]
[tex]Times = 72[/tex]
Answer:
The answer would be: The mistake in Kevin's calculation is when calculating P(Red or Green).
Step-by-step explanation:
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