Answer:
W = 1203.54 J = 1.2 KJ
Explanation:
The work done on an object is defined as the product of the displacement of the object and the force applied in the direction of that displacement. Hence, the formula for work done is as follows:
[tex]W = FdCos \theta[/tex]
where,
W = Work done by Mike = ?
F = Force applied by Mike = 22.5 N
θ = Angle between force and displacement = 35°
d = displacement of sled = 65.3 m
Therefore,
[tex]W = (22.5\ N)(65.3\ m)Cos\ 35^o[/tex]
W = 1203.54 J = 1.2 KJ
