Answer:
[tex]1.4*10^-7N[/tex]
Explanation:
Step one:
given data
mass m1= 87 kg
mass m2=60kg
sitting distance r= 0.5m
The gravitational constant G= 6.67*10^-11Nm^2/kg^2
Required
The Force of attraction between the two bodies
Step two:
Applying the formula for the force of attraction by gravity on two bodies
[tex]F=\frac{Gm1m2}{r^2}[/tex]
substituting our data we have
[tex]F=\frac{6.67*10^-^1^1 *87*60}{0.5^2}\\\\F=\frac{3.48174*10^-^7}{0.25^2}\\\\F=1.4*10^{-7}N[/tex]
