Answer:
The magnitude of joes net force is 58.9.
Explanation:
The magnitude of the net force is given by:
[tex] F_{net} = \sqrt{F_{x}^{2} + F_{y}^{2}} [/tex]
Where:
[tex] F_{x}[/tex]: is the force in the horizontal direction = 57.0
[tex] F_{y}[/tex]: is the force in the vertical direction = -15.0
[tex] F_{net} = \sqrt{(57.0)^{2} + (-15.0)^{2}} = 58.9 [/tex]
Therefore, the magnitude of joes net force is 58.9.
I hope it helps you!
