contestada

the burning time of a very large candle is normally distributed, with a mean of 2500 hours and a standard deviation of 20 hours. find the z-score that corresponds to a lifespan of 2470 hours.
a. 2.5
b. 1.5
c. -1.5
d -2.5​

Respuesta :

absor201

Answer:

Value of z-score is -1.5

Option C is correct.

Step-by-step explanation:

We are given

Mean = 2500 hrs

Standard Deviation = 20 hours

X = 2470

We need to find z-score

The formula used to calculate z-score is: [tex]z-score=\frac{x-\mu}{\sigma} \\[/tex]

Putting values of x, mean and standard deviation in the formula

[tex]z-score=\frac{x-\mu}{\sigma} \\z-score=\frac{2470-2500}{20} \\z-score=-1.5[/tex]

So, value of z-score is -1.5

Option C is correct.

Otras preguntas