TheMathOfBillNye
contestada

Which of the following tables shows the correct steps to transform x2 + 10x + 24 = 0 into the form (x − p)2 = q?
[p and q are integers] (5 points)

Select one:
a.
Step 1 x2 + 10x + 24 − 1 = 0 − 1
Step 2 x2 + 10x + 23 = −1
Step 3 (x + 5)2 = −1
b.
Step 1 x2 + 10x + 24 − 2 = 0 − 2
Step 2 x2 + 10x + 22 = −2
Step 3 (x + 5)2 = −2
c.
Step 1 x2 + 10x + 24 + 2 = 0 + 2
Step 2 x2 + 10x + 26 = 2
Step 3 (x + 5)2 = 2
d.
Step 1 x2 + 10x + 24 + 1 = 0 + 1
Step 2 x2 + 10x + 25 = 1
Step 3 (x + 5)2 = 1

Respuesta :

PikachuDenkiUwU

I would say D or A

x^2 + 10x + 24 = 0

You would use

a^2 + 2ab + b^2 = (a+b)^2

x^2 + 10x + 24 = x^2  + 2 times x times 5 + 24

What you have is

2ab = 2 times x times 5  b = 5

so b^2 has to equal 25 = 5^2

you have 24 but you have to increase it by 1

x^2 + 10x + 24 = 0

x^2 + 2 times x times 5 + 24 = 0

x^2 + 2 times x times 5 + 24 + 1 = 0 + 1

x^2 + 2 times x times 5 + 25 = 1

x^2 + 2 times x times 5 + 5^2 = 1

(x+5)^2 = 1

The correct steps to transform x2 + 10x + 24 = 0 into the form (x − p)2 = q is A and D.

What is factorization?

factorization is the method of breaking a number into smaller numbers that multiplied together will give that original form.

WE know that

[tex]a^2 + 2ab + b^2 = (a+b)^2[/tex]

[tex]x^2 + 10x + 24 \\\\= x^2 + 2 \times x \times 5 + 24[/tex]

so b^2 has to equal 25 = 5^2

Now, x^2 + 10x + 24 = 0

[tex]x^2 + 2 \times x \times5 + 24 = 0\\\\x^2 + 2 \timesx \times5 + 24 + 1 = 0 + 1\\x^2 + 2 \timesx \times5 + 25 = 1\\x^2 + 2 \timesx \times5 + 5^2 = 1\\(x+5)^2 = 1[/tex]

Therefore, the correct steps to transform x2 + 10x + 24 = 0 into the form (x − p)2 = q is A and D.

Learn more about prime factorization here:

https://brainly.com/question/10454590

#SPJ5

Otras preguntas