Mass of Hydrogen gas required to react : 0.936 g
Reaction on Nitrogen gas and Hydrogen gas to produce Ammonia gas
N₂ (g) + 3 H₂ (g) ⇒ 2 NH₃ (g)
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol
so mol Nitrogen for 3.5 L at STP :
[tex]\tt mol=\dfrac{3.5~L}{22.4~L}=0.156[/tex]
From the equation, mol ratio of N₂ : H₂ = 1 : 3, so mol H₂ :
[tex]\tt \dfrac{3}{1}\times 0.156=0.468[/tex]
then mass of Hydrogen(MW= 2 g/mol) :
[tex]\tt mass=mol\times MW\\\\mass=0.468\times 2\\\\mass=0.936~g[/tex]
