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A boulder with a mass of 2,500 kg resting on a ledge 200 m above the ground falls. If the boulder’s ME is conserved, what is the speed of the boulder just before it hits the ground?

Respuesta :

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Answer:

nitial GPE = final KE 2500*10*200 = ½ 2500*v^2 v^2 = 2*10*200 v= 63.24 m/sec

Explanation:

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