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Point [tex]P^1[/tex] is the image of P(6,0) under the translations (x, y) → (x - 6, y - 1) What are the coordinates of [tex]P^1[/tex]?

Respuesta :

Answer:

(0, -1)

Step-by-step explanation:

(x, y) → (x - 6, y - 1)

Apply the rule to point 'P'.

[tex](6,0)\rightarrow(6-6,0-1)\rightarrow\boxed{(0,-1)}[/tex]

Hope this helps.

lambospeed6070

Answer:

thanks for the points doe

Step-by-step explanation:

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