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Answer:
see below
Step-by-step explanation:
Make use of the quadratic formula.
For equation ax² +bx +c = 0, the solutions are ...
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
Here, you have a=1, b=-1, c=1, so the solutions are ...
[tex]x=\dfrac{-(-1)\pm\sqrt{(-1)^2-4(1)(1)}}{2(1)}=\dfrac{1\pm\sqrt{1-4}}{2}=\dfrac{1\pm i\sqrt{3}}{2}\\\\\boxed{x=\dfrac{1+i\sqrt{3}}{2}\text{ and }x=\dfrac{1-i\sqrt{3}}{2}}[/tex]
