What the trinomial factor of this problem
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Answer:
[tex]x^2-9x+20=(x-4)(x-5)[/tex]
Step-by-step explanation:
Factoring a Trinomial
A second-degree trinomial can be expressed as:
[tex]ax^2+bx+c[/tex]
It can be factored, i.e., converted to a product instead of a sum of terms in several ways.
We'll use the grouping method.
Factor:
[tex]x^2-9x+20[/tex]
Split the second term into two terms:
[tex]x^2-4x-5x+20[/tex]
Factor x on the first two terms and -5 on the last two terms:
[tex]x(x-4)-5(x-4)[/tex]
Now factor out x-4:
[tex](x-4)(x-5)[/tex]
Thus:
[tex]\mathbf{x^2-9x+20=(x-4)(x-5)}[/tex]