Respuesta :

Answer:

It is answer A) 5x^8y^8z^3 (sq rt 2y)

Step-by-step explanation:

1. Factor out the perfect square

(sqr rt) 5^2 × 2x^16 × y^16 xyz^6

2. Split each factor to their own square root

3. Simplify these roots

Answer:

A

Step-by-step explanation:

First let's factor 50. This will look like this: 2*5*5. Since there are two 5s, together they form a perfect square so we can bring it out of the square root. This is what we have so far now: [tex]5\sqrt{2x^{16} y^{17} z^{6} }[/tex]. Now we should move on to [tex]x^{16}[/tex], since 16 is an even number, we can just divide it in half and put x to the power of 16/2 outside the square root. This is what we have so far: [tex]5x^{8} \sqrt{2y^{17}z^{6} }[/tex]. Now let's work on [tex]y^{17}[/tex]. Since 17 is an odd number, we will separate it like this: 16 + 1. Now we can divide 16 by 2 and put y to the power of 16 divided by 2 outside of the square root, but the last [tex]y^{1}[/tex] will need to continue inside. So this is what we have so far: [tex]5x^{8}y^{8} \sqrt{2y z^{6}}[/tex]. Now all we have to do is take care of the [tex]z^{6}[/tex]. Since 6 is even we can just divide it by 2 and put the z to the power of 6 divided by 2 outside of the square root. This is what we have: [tex]5x^{8}y^{8} z^{3} \sqrt{2y}[/tex].

We are done!

I hope this made sense. Please give Brainliest!