Answer:
1.20 × 10²⁴ atoms He
General Formulas and Concepts:
Chemistry - Atomic Structure
Explanation:
Step 1: Define
8.00 g He
Step 2: Identify Conversions
Avogadro's Number
Molar Mass of He - 4.00 g/mol
Step 3: Convert
[tex]8.00 \ g \ He(\frac{1 \ mol \ He}{4.00 \ g \ He} )(\frac{6.022 \cdot 10^{23} \ atoms \ He}{1 \ mol \ He} )[/tex] = 1.2044 × 10²⁴ atoms He
Step 4: Check
We are given 3 sig figs. Follow sig fig rules and round.
1.2044 × 10²⁴ atoms He ≈ 1.20 × 10²⁴ atoms He
