A colony of insects doubles every day. If the colony has 5 insects todayHow many will be present in 20 days?
a.1310720
b. 2621440
c. 5242880
d. 10485760

Respuesta :

The answer is C all I did was multiply 5*2 and repeat 20 times

5242880 insects would be present in 20 days.

The correct answer is an option (c)

What is the formula of exponential growth?

"[tex]f(x)=ab^x[/tex],

where a is the initial value

b is the growth rate

x is time. "

For given question,

Suppose the function for the population growth is,

[tex]A(t)=A_0\times b^t[/tex]                    

A colony of insects doubles every day.

⇒ b = 2

The colony has 5 insects today.

⇒ [tex]A_0=5[/tex]

So, the exponential growth function would be,

[tex]A(t)=5\times 2^t[/tex]                   ...........(1)

We need to find the number of insects after 20 days,

From equation (1),

[tex]\Rightarrow A(20)=5\times 2^{20}\\\\\Rightarrow A(20)=5\times 1048576\\\\\Rightarrow A(20)=5242880[/tex]

Therefore, 5242880 insects would be present in 20 days.

The correct answer is an option (c)

Learn more about the exponential growth here,

brainly.com/question/11487261

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