Respuesta :
Answer:
We have the system:
3y>2x+12
2x+y≤-5
The first step will be to write the inequalities as lines:
y > (2x + 12)/3
y ≤ -5 - 2 x
Now that the equations are written in slope-intercept form, we just need to draw the lines.
In the first case, we have the symbol ">", which means that the line will be a dashed line, and the shaded area will be above that line.
In the second equation we have the symbol "≤", this means that the line will be a solid line, and the shaded area will be below that line.
The graph of both inequalities is shown below. Where the solution to the system is the double shaded area.
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Answer:
Thanks to Facundo doing all the work, all I did was plug in the numbers on a graphing calculator.
Step-by-step explanation:
Using the graphing calculator, "y>(2x+12)/3" has points at (-6,0) and (0, 4) and isn't shaded because there isn't a line under the greater than/less than sign.
Using the graphing calculator again, we plug in the inequality "y≤-5-2x". This has points at (-5, 0) and (0, -5) and is shaded because there is a line under the greater than/less than sign. A picture of this is attached.
Again, thank you Facundo. Refer to his explanation to find out how to make the inequalities lines.
Please rate this to give me feedback if this kind of format is good for answering questions.
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