The sum of the squares of two different numbers is less than or equal to 49. Twice one of the numbers squared is less than the other number. Which system of inequalities represents these criteria?

Possible answers:
x^2 + y^2 ≤ 49 and 2x^2 < y
x^2 + y^2 ≥ 49 and 2x^2 < y
x^2 + y^2 ≤ 49 and x^2 < 2y
x^2 + y^2 ≥ 49 and x^2 < 2y

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Arlett08 Arlett08 · Answer 1 · 2021-02-23T15:57:12+01:00

Answer:

A. x2 + y2 ≤ 49 and 2x2 < y

Step-by-step explanation:

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saimaparvezVT saimaparvezVT · Answer 2 · 2022-07-22T07:01:09+02:00

This system of inequalities represents is x² + y² ≤ 49 and 2x² < y

Inequality is the defined as mathematical statements that have a minimum of two terms containing variables or numbers is not equal.

Let the numbers x and y,

According to 1st condition,

The sum of the squares of two different numbers is less than or equal to 49 :

x² + y² ≤ 49

According to 2nd condition,

Twice one of the numbers squared is less than the other number :

2x² < y

Hence, this system of inequalities represents is x² + y² ≤ 49 and 2x² < y

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