The accompanying diagram shows a flagpole that stands on level ground. Two cables, r and s,
are attached to a pole at a point 20 feet above the ground. The combine length of the two cables
is 70 feet. If cable r is attached to the ground 8 feet from the base of the pole, what is the
measure of the angle, x, to the nearest degree, that cable s makes with the ground?

The accompanying diagram shows a flagpole that stands on level ground Two cables r and s are attached to a pole at a point 20 feet above the ground The combine class=

Respuesta :

Answer:

x = [tex]24^{o}[/tex]

Step-by-step explanation:

r + s = 70 feet

Applying Pythagoras theorem to the triangle formed by cable r;

[tex]/hyp/^{2}[/tex] = [tex]/adj1/^{2}[/tex] + [tex]/adj2/^{2}[/tex]

[tex]/r/^{2}[/tex] = [tex]/20/^{2}[/tex] + [tex]/8/^{2}[/tex]

[tex]r^{2}[/tex] = 400 + 64

   = 464

r = [tex]\sqrt{464}[/tex]

 = 21.541

Length of cable r is 21.54 feet.

So that,

r + s = 70 feet

21.54 feet + s = 70 feet

s = 70 feet - 21.54 feet

  = 48.46 feet

Length of cable s is 48.46 feet.

Applying trigonometric function to the triangle formed by cable s, we have;

Sin θ = [tex]\frac{opposite}{hypotenuse}[/tex]

Sin x = [tex]\frac{20}{48.46}[/tex]

        = 0.4127

x = [tex]Sin^{-1}[/tex] 0.4127

  = 24.3746

x = [tex]24^{o}[/tex]

The measure of angle that s makes with the ground is approximately [tex]24^{o}[/tex].