Answer:
1.37dm³
Explanation:
To solve this problem, let us write the reaction expression:
2KClO₃ → 2KCl + 3O₂
Now, mass of KClO₃ is 5g, let us find the number of moles;
Number of moles = [tex]\frac{mass}{molar mass}[/tex]
Molar mass of KClO₃ = 39 + 35.5 + 3(16) = 122.5g/mol
Now;
Number of moles = [tex]\frac{5}{122.5}[/tex] = 0.04mole
So;
2 moles of KClO₃ will produce 3 moles of oxygen gas
0.04 mole of KClO₃ will produce [tex]\frac{3 x 0.04} {2}[/tex] = 0.06moles
At STP;
1 mole of gas has a volume of 22.4dm³
0.06 mole of oxygen gas will have a volume of 22.4 x 0.06 = 1.37dm³
