the graph of y=x^2 +4x + 3 is shown
a) what are the coordinates of the turning point
b) what are the coordinates of the roots of the equation x^2+4x+3=0

Respuesta :

Answer:

a) -2, -1

b) (-3,0) and (-1,0)

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From the graph of the given equation

the coordinates of the turning point is [tex](-2,-1)[/tex]

The coordinates of the roots of the equation [tex]x^2+4x+3=0[/tex] are [tex](-3,0) \; and \;( -1,0)[/tex]

Given :

the graph of y=x^2 +4x + 3 is shown

The graph of [tex]y=x^2 +4x + 3[/tex] is attached below

From the graph we can see that , the vertex is (-2,-1)

The graph changes direction at the point (-2,-1)

so we can say that there is only one turning point at [tex](-2,-1)[/tex]

Now we find out the roots of the equation

roots are the points where the graph crosses or touches x axis

The graph crosses x axis at [tex]-3 \; and \; -1[/tex]

The coordinates of the roots of the equation [tex]x^2+4x+3=0[/tex] are [tex]-3 \; and \; -1[/tex]

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