Respuesta :
The bean bag’s path is part of a curve that is a parabola and to the nearest second, the bean bag was in the air for 1 second(s).
What is projectile motion?
Projectile motion is the motion of the body, when it is thrown in the air taking the action of gravity on it.
The parametric equation for x and y can be given as,
[tex]x =x_o+ v_o\cos(\theta)t \\y =y_o -\dfrac{1}{2}at^2 + (v_o\sin(\theta))t[/tex]
Here, (vo) is the initial speed, (h) is the height and θ is the angle of throw.
The player throws a bean bag from the height of 3 feet with an initial velocity of 34 feet per second at an angle of 30º.
Let suppose the time is t second. Thus, the parametric equation that represents this situation are,
[tex]x = (34\cos(30^o)t \\y = -16t^2 + (34\sin(30^o))t + 3[/tex]
The bean bag’s path is part of a curve. This path is in the form of parabola.
To the nearest second, the bean bag was in the air for 1 second(s).
Thus, the bean bag’s path is part of a curve that is a parabola and to the nearest second, the bean bag was in the air for 1 second(s).
Learn more about the projectile motion here;
https://brainly.com/question/24216590
