Find angle 1
(5x+6)° and (7x-18)°
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Answer:
Step-by-step explanation:
<1 is the supplement of 5x + 5. You have to assume that the almost horizontal lines are parallel. In addition, two angles on the same side of a transversal across two parallel lines and are interior angles are supplementary.
5x + 6 + 7x - 18 = 180 Add like terms
12x - 12 = 180 Add 12 to both sides
12x = 180 + 12
12x = 192 Divide by 12
x = 192 /12
x = 6
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5x + 6 = 5*12 + 6
5x + 6 = 60 + 6
5x + 6 = 66
<1 + 66 = 180
<1 = 180 - 66
<1 = 114