Answer:
E = 0.994 J
Explanation:
Given that,
Total no of photons, [tex]n=1.5\times 10^{13}[/tex]
The wavelength of gamma radiation, [tex]\lambda=3\times 10^{-12}\ m[/tex]
We need to find the total energy in given no of photons. The formula for the energy of a photon is given by :
[tex]E=\dfrac{hc}{\lambda}[/tex]
For n photons,
[tex]E=\dfrac{nhc}{\lambda}\\\\E=\dfrac{1.5\times 10^{13}\times 6.63\times 10^{-34}\times 3\times 10^8}{3\times 10^{-12}}\\\\=0.994\ J[/tex]
So, the total energy is 0.994 J.
