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During a safety test, a car hits a wall and stops in 0.55 s. The net force on the car is 6500 N during the collision.
What is the magnitude of the change in momentum of the car?

ASAP WILL GIVE BRAINLIEST During a safety test a car hits a wall and stops in 055 s The net force on the car is 6500 N during the collision What is the magnitud class=

Respuesta :

Answer:

The change in momentum of the car is 3575 Kg.m/s

Explanation:

Impulse and Momentum

The impulse (J) experienced by the object equals the change in momentum of the object (Δp).

The formula that represents the above statement is:

J = Δp

The impulse is calculated as

J = F.t

Where F is the applied force and t is the time.

The car hits a wall with a force of F=6500 N and stops in 0.55 s. Thus, the impulse is:

J = 6500 * 0.55

J = 3575 Kg.m/s

The change in momentum of the car is:

[tex]\Delta p= J = 3575\ Kg.m/s[/tex]

The change in momentum of the car is 3575 Kg.m/s