[tex]y-2=-\frac{1}{3}(x+6)\\y=-\frac{1}{3}(x+6)+2[/tex]
Simply move -2 to another side.
[tex]y=-\frac{x}{3}-2+2[/tex]
Distribute -1/3 in (x+6)
[tex]y=-\frac{x}{3}[/tex] ---> Answer
Answer:
x + 3y = 0
Step-by-step explanation:
The equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
Given
y - 2 = - [tex]\frac{1}{3}[/tex] (x + 6) ← distribute
y - 2 = - [tex]\frac{1}{3}[/tex] x - 2 ( add 2 to both sides )
y = - [tex]\frac{1}{3}[/tex] x ( multiply through by 3 to clear the fraction )
3y = - x ( add x to both sides )
x + 3y = 0 ← in standard form
