Respuesta :
Answer: [tex]CaCO_3(s)\rightarrow CaO(s)+CO_2(g)[/tex] , 0.533 L
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
[tex]CaCO_3(s)\rightarrow CaO(s)+CO_2(g)[/tex]
According to avogadro's law, 1 mole of every substance occupies 22.4 L of volume at STP.
Number of moles =[tex]\frac{\text {given mass}}{\text {Molar mass}}[/tex]
moles of calcium carbonate = [tex]\frac{2.38g}{100g/mol}=0.0238mol[/tex]
As 1 mole of calcium carbonate produces = 22.4 L of carbon dioxide at STP
Thus 0.0238 moles of calcium carbonate produces =[tex]\frac{22.4 L}{1}\times 0.0238=0.533L[/tex] of carbon dioxide at STP
The balanced equation is [tex]CaCO_3(s) \rightarrow CaO(s) + CO_2(g)[/tex]
The number of liters of carbon dioxide that should be produced is 0.533L
Law of conversation of mass:
As per this law, the mass could neither be developed nor be destroyed. So, the mass of products should be equivalent to the mass of reactants. The number of atoms of every element has to be the similar on reactant and product sides. Due to this, the chemical equations are balanced.
[tex]CaCO_3(s) \rightarrow CaO(s) + CO_2(g)[/tex]
Avogadro's law:
As per this law, 1 mole of every substance occupies 22.4 L of volume at STP.
So,
We know that
Number of moles = [tex]given\ mass \div molar\ mass[/tex]
Now the moles of calcium carbonate is [tex]= 2.38 \div 100[/tex] = 0.0238 mol
Since 1 mole of calcium carbonate generated = 22.4 L of carbon dioxide at STP
So, 0.0238 moles of calcium carbonate generated
[tex]= 22.4 \div 1 \times 0.0238 \\\\= 0.533L[/tex]
of carbon dioxide at STP
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