contestada

What volume (in mL) of 0.51 M H2SO4(aq) solution is necessary to completely react with 103 mL of 0.36 M KOH(aq)

Respuesta :

Answer: 36.3 ml

Explanation:

According to the neutralization law,

[tex]n_1M_1V_1=n_2M_2V_2[/tex]

where,

[tex]n_1[/tex] = basicity [tex]H_2SO_4[/tex] = 2

[tex]M_1[/tex] = molarity of [tex]H_2SO_4[/tex] solution = 0.51 M

[tex]V_1[/tex] = volume of  [tex]H_2SO_4[/tex] solution = ?

[tex]n_2[/tex] = acidity of [tex]KOH[/tex] = 1

[tex]M_1[/tex] = molarity of [tex]KOH[/tex] solution = 0.36 M

[tex]V_1[/tex] = volume of  [tex]KOH[/tex] solution = 103 ml

Putting in the values we get:

[tex]2\times 0.51\times V_1=1\times 0.36\times 103[/tex]

[tex]V_1=36.3ml[/tex]

Therefore, volume of [tex]H_2SO_4[/tex] required is 36.3 ml

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