Answer:
23 seconds
Explanation:
Step one:
given data
mass m= 170kg
The spring constant is 1250 N/m
Required
The period required for 10 oscillations
Step two:
The expression relating period, mass, and spring constant is
[tex]T=2 \pi \sqrt{\frac{m}{k} } \\[/tex]
substituting our data we have
[tex]T=2 *3.142 \sqrt{\frac{170}{1250} } \\\\T=6.284* \sqrt{0.136}\\\\T=6.284*0.3687\\T=2.3s[/tex]
A Period is defined as the time required to complete one full oscillation
hence, having found the period to be 2.3 seconds, the time required for 10 oscillations will be 2.3*10= 23seconds
