Answer:
[tex]\frac{x}{y} \frac{5x}{\frac{x^{2} -4}{\frac{8x}{x+2} } }\\\\=\frac{5x(x+2)}{8x(x^{2} -4)}\\\\=\frac{5(x+2)}{8(x+2)(x-2)}\\\\=\frac{5}{8(x-2)}\\\\=\frac{5}{8}.\frac{1}{x-2}[/tex]
Step-by-step explanation:
Step-by-step explanation:
[tex] \frac{ \frac{5x}{ {x}^{2} - 4 } }{ \frac{8x}{x + 2} } = \frac{5x}{ {x}^{2} - 4 } \times \frac{x + 2}{8x} = \frac{5x + 10}{ {8x}^{2} - 32} \\ [/tex]
hope it helps:)
