Answer:
V₂ = 651.34 mL
Explanation:
Given data:
Initial volume = 255 mL
Initial pressure = 2.40 atm
Initial temperature = 7°C (7 +273 = 280 K)
Final temperature = 25°C (25 +273 = 298 k)
Final volume = ?
Final pressure = 1 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 2.40 atm × 255 mL × 298 K / 280 K × 1 atm
V₂ = 182376 atm .mL. K / 280 K.atm
V₂ = 651.34 mL
