pH of the Sr(OH)₂ solution : 12.6
pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.
pH = - log [H⁺]
Sr (OH) ₂ solution is a base with valence 2, so we determine the pOH from the OH ion concentration - which is expressed by pOH = - log [OH -]. After that we determine the pH value from the relationship:
[H⁺] [OH⁻] = Kw=10⁻¹⁴
pH + pOH = 14
Sr(OH)₂⇒Sr²⁺+2OH⁻
From equation [Sr(OH)₂] : [OH⁻]=1 : 2, so [OH⁻]=
[tex]\tt [OH^-]=2\times 2.10^{-2}=4.10^{-2}~M[/tex]
[tex]\tt pOH=-log[OH^-]\\\\pOH=-log~4.10^{-2}\\\\pOH=2-log~4\rightarrow 1.398 \\\\pH+pOH=14\\\\pH=14-1.398\\\\pH=12.6[/tex]
pH is the measurement of the concentration of hydrogen or hydronium ion in an aqueous solution. The pH of strontium hydroxide is 12.6.
The pH is the potential of hydrogen or the negative log of its concentration.
First, calculate the pOH of strontium hydroxide by:
[tex]\begin{aligned} \rm pOH &= \rm - log [OH ^{-}]\\\\&= \rm -log [4\times10^{-2}]\\\\&= 1.398\end{aligned}[/tex]
Now, calculate pH from pOH as:
[tex]\begin{aligned}\rm pH &= 14 - \rm pOH\\\\&= 14 - 1.398\\\\&= 12.6\end{aligned}[/tex]
Therefore, 12.6 is the pH of strontium hydroxide.
Learn more about pH here:
https://brainly.com/question/10725749
