Answer:
1 × 10²⁴ atoms O
General Formulas and Concepts:
Chemistry - Atomic Structure
Explanation:
Step 1: Define
30 g O
Step 2: Identify Conversions
Avogadro's Number
Molar Mass of O - 16.00 g/mol
Step 3: Convert
[tex]30 \ g \ O(\frac{1 \ mol \ O}{16.00 \ g \ O} )(\frac{6.022 \cdot 10^{23} \ atoms \ O}{1 \ mol \ O} )[/tex] = 1.12913 × 10²⁴ atoms O
Step 4: Check
We are given 1 sig fig. Follow sig fig rules and round.
1.12913 × 10²⁴ atoms O ≈ 1 × 10²⁴ atoms O