A company produces fruity drinks that contain a percentage of real fruit juice. Drink A contains 20% real fruit juice and Drink B contains 15% real fruit juice. The company used 100.5 liters of real fruit juice to make 30 more liters of Drink A than liters of Drink B. Write a system of equations that could be used to determine the number of liters of Drink A made and the number of liters of Drink B made. Define the variables that you use to write the system.

Multiplying a number by 0.2 is the same as calculating 20% of it and same goes with 15% and 0.15. This makes our equation for the amount of fruit juice:

0.2a + 0.15b = 100.5

We know what the difference between a and b will be 30 liters so:

a - b = 30

Now we have our system of equations

To cancel out a, we can multiply the first equation by -5 so we will now have:

-a - 0.75b = -502.5

a - b = 30

Adding these two equations together, we get:

-1.75b = -472.5

Both sides are negative, so we can take the negative signs away.

1.75b = 472.5

Now divide both sides by 1.75

b = 270

Plugging 270 into b, we have:

a - b = 30

a - 270 = 30

Add 270 to both sides

a = 300

There needs to be 300 liters of Drink A and 270 liters of Drink B

fichoh fichoh · Answer 2 · 2021-09-21T13:34:54+02:00

The system of linear equations which could be used to find the amount in litres of drinks A and B are :

(0.2a + 0.15b) = 100.5
a - b = 30

Let :

Amount of drink A = a

Amount of drink B = b

Percentage of real fruit juice for drink A = 20%

Percentage of real fruit juice for drink B = 15%

Total litres made = 100.5

(Amount of drink A × percentage) + (Amount of drink B × percentage) = Total litres

(0.2a + 0.15b) = 100.5 - - - - - (1)

The difference between the amount of drink A and B made :

Drink A is 30 liters more than B :

a - b = 30 - - - - - (2)

The system of equations required to determine the amount of drink A and B made are :

(0.2a + 0.15b) = 100.5
a - b = 30

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