Answer:
option D
Step-by-step explanation:
[tex]\sqrt{10x+50}=x+5\\\\(\sqrt{10x+50})^2=(x+5)^2\\\\10x+50=x^2+10x+25\\\\0=x^2+10x-10x+25-50\\\\0=x^2-25\\\\0=(x-5)(x+5)\\\\x=5\\\\x=-5[/tex]
now trying for the original equation
[tex]\sqrt{10(5)+50}=5+5\\\\\sqrt{50+50}=10\\\\\sqrt{100}=10\\\\10=10[/tex]
and
[tex]\sqrt{10(-5)+50}=-5+5\\\\\sqrt{-50+50}=0\\\\\sqrt{0}=0\\\\0=0[/tex]
so it's option D
