Eliana2007
contestada

You drop a bowling ball and it falls with an acceleration of 10 m/s2. The ball has a mass of 5 kg. How much force is causing the ball to fall?

Respuesta :

kritika3375

Explanation:

Given

acceleration (a) = 10 m/s²

mass (m) = 5 kg

Force (F) = ?

We know

F = m * a

= 5 * 10

= 50 Newton

The force is 50 N

Hope it will help :)

Sarah06109

Answer:

[tex]\boxed {\boxed {\sf 50 \ Newtons }}[/tex]

Explanation:

Force can be found using the following formula.

[tex]F=m*a[/tex]

where F is the force, m is the mass, and a is the acceleration.

1. Define Values

We know the acceleration of the bowling ball is 10 m/s² and the mass is 5 kilograms.

[tex]a= 10 \ m/s^2 \\m= 5 \ kg[/tex]

2. Calculate Force

Substitute the values into the formula.

[tex]F= 5 \ kg * 10 \ m/s^2[/tex]

Multiply.

[tex]F= 50 \ kg*m/s^2[/tex]

  • 1 kilogram meter per square second is equal to 1 Newton.
  • Our answer of 50 kg*m/s² is equal to 50 N

[tex]F=50 \ N[/tex]

The force causing the ball to fall is 50 Newtons

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