Help with this please. I’d appreciate if you showed the steps and the answer. Thanks a lot!
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[tex]\boxed{\boxed{\pink{\bf \leadsto Hence \ the \ horizontal \ distance \ is \ 11.47 \ feet . }}}[/tex]
Given that Scott is using a 12 foot ramp . And the height of the truck is 3.5 feet from the ground. And we need to find the horizontal distance of the ramp reaches the ground of the truck .
Here will be a formation of a right angled triangle in which the
On using Pythagoras Theorem ,
[tex]\red{\bf \implies base^2+perpndicular^2=hypontenuse^2}\\\\\bf\implies (12 ft )^2 = base^2 + (3.5 ft )^2\\\\\bf\implies 144ft^2 = base^2+12.25 ft^2 \\\\\bf\implies base^2 = 144ft^2-12.25ft^2 \\\\\bf\implies base^2 = 131.75 ft^2\\\\\bf\implies base=\sqrt{131.75ft^2}\\\\\bf\implies\boxed{\red{\bf base = 11.47 ft }}[/tex]