Answer:
5
(3a²b³c)³(2a⁴b²c²)³
= (3a⁶b⁹c³)(8a¹²b⁶c⁶)
= 24a¹⁸b¹⁵c⁹
14
⁴√(81a¹⁶b¹²c⁹)
= (⁴√81)(⁴√a¹⁶)(⁴√b¹²)(⁴√c⁹)
[tex]= 3 (a^{\frac{16}{4} }) (b^{\frac{12}{4} } ) (c^{\frac{9}{4} } )[/tex]
[tex]= 3a^{4} b^{3} c^{\frac{9}{4} }[/tex]
