Answer:
The potential difference between the points is: 0.1 V
Explanation:
Given
To determine
The potential difference between the points is
We can use the formula to determine the potential difference between the points
[tex]V_A-V_B=\frac{W}{q_0}[/tex]
where W is done by moving charge q₀ from point A and point B
substituting W = 2J, and q₀ = 20 C
[tex]=\frac{2}{20}[/tex]
[tex]= 0.1[/tex] V
Therefore, the potential difference between the points is: 0.1 V