Polonium-218 undergoes beta decay, converting a neutron into a proton. Then the daughter isotope undergoes another beta decay, again converting a neutron into a proton. Which equation correctly describes this process? Use the periodic table link from the tools bar to answer the question.

Polonium218 undergoes beta decay converting a neutron into a proton Then the daughter isotope undergoes another beta decay again converting a neutron into a pro class=
Polonium218 undergoes beta decay converting a neutron into a proton Then the daughter isotope undergoes another beta decay again converting a neutron into a pro class=
Polonium218 undergoes beta decay converting a neutron into a proton Then the daughter isotope undergoes another beta decay again converting a neutron into a pro class=
Polonium218 undergoes beta decay converting a neutron into a proton Then the daughter isotope undergoes another beta decay again converting a neutron into a pro class=

Respuesta :

Answer: [tex]^{218}_{84}Po \rightarrow ^{218}_{85}At + ^{0}_{-1}e[/tex] is the correct equation for beta decay.

Explanation:

When a beta particle, that is, [tex]^{0}_{-1}e[/tex] is emitted in a radioactive decay then it is known as beta decay.

Therefore, beta decay of Polonium-218 is as follows.

[tex]^{218}_{84}Po \rightarrow ^{218}_{85}At + ^{0}_{-1}e[/tex]

Therefore, we can conclude that [tex]^{218}_{84}Po \rightarrow ^{218}_{85}At + ^{0}_{-1}e[/tex] is the correct equation for the given beta decay.  

Answer:

A

Explanation:

The top dudes answer summed up.